2x^2+16=652

Solution for 2x^2+16=652 equation:

2x^2+16=652

We move all terms to the left:

2x^2+16-(652)=0

We add all the numbers together, and all the variables

2x^2-636=0

a = 2; b = 0; c = -636;
Δ = b2-4ac
Δ = 02-4·2·(-636)
Δ = 5088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5088}=\sqrt{16*318}=\sqrt{16}*\sqrt{318}=4\sqrt{318}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{318}}{2*2}=\frac{0-4\sqrt{318}}{4}
=-\frac{4\sqrt{318}}{4}
=-\sqrt{318}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{318}}{2*2}=\frac{0+4\sqrt{318}}{4}
=\frac{4\sqrt{318}}{4}
=\sqrt{318}
$